Zimlet with PHP API??

[xrickung]

Wondering if it is possible to write a zimlet with PHP API?
And if yes can you please guide me a little bit.

Thank you,

[xrickung]

Sorry
I mean to integrate zimbra to an external apllication that provides PHP API (with zimlet).

Cheers,

[scotty]

You'd need to write a shim to the PHP API, like a REST or SOAP web service, or just a basic web page, then access that interface from your Zimlet via the Zimbra Proxy.

// call the web service to retrieve ABC
var service_url = 'http://....' + '?what=ABC';
var url = ZmZimletBase.PROXY + AjxStringUtil.urlComponentEncode(service_url);

AjxRpc.invoke(null, url, null, new AjxCallback(this, this._handler), true);

Your PHP would look like:

<?php
require 'API';

$what = $_REQUEST['what'];
if (valid_what($what)) {
  $resp = API_call($what);
  echo what_to_html($resp);
} else {
...
}

[xrickung]

That's very helpful now I can see how the the integration works clearer, thanks scotty!!!

[ashish_clarion]

Originally Posted by scotty

You'd need to write a shim to the PHP API, like a REST or SOAP web service, or just a basic web page, then access that interface from your Zimlet via the Zimbra Proxy.

// call the web service to retrieve ABC
var service_url = 'http://....' + '?what=ABC';
var url = ZmZimletBase.PROXY + AjxStringUtil.urlComponentEncode(service_url);

AjxRpc.invoke(null, url, null, new AjxCallback(this, this._handler), true);

Your PHP would look like:

<?php
require 'API';

$what = $_REQUEST['what'];
if (valid_what($what)) {
  $resp = API_call($what);
  echo what_to_html($resp);
} else {
...
}

I got 403 forbidden error while passing my local url.

I am passing 'http://localhost/test.php?action=test'. Its give me 403 forbidden error in response.

so my url is look like "/service/proxy?target=http%3A%2F%2Flocalhost%2Ftest.php"

Can you please suggest where I am wrong.

[JoshuaPrismon]

Originally Posted by ashish_clarion

I got 403 forbidden error while passing my local url.

I am passing 'http://localhost/test.php?action=test'. Its give me 403 forbidden error in response.

so my url is look like "/service/proxy?target=http%3A%2F%2Flocalhost%2Ftest.php"

Can you please suggest where I am wrong.

Check your zimlet xml file, and make sure you have given it permission to access outside resources.

[ashish_clarion]

Yes, I have made allowedDomains "*" in config_template.xml but still I am not able to request on that.
I am developing zimlet in Zimbra Desktop under _dev dir.

[tdesorbaix]

Originally Posted by ashish_clarion

I am developing zimlet in Zimbra Desktop under _dev dir.

That is the problem.
The allowedDomains in the config_template.xml is set when you deploy the zimlet.

Just deploy the zimlet once or add the allowedDomains with the CLI.

[ashish_clarion]

Thanx dear,

Problem solved now I know what the problem

[ronanhigg]

Originally Posted by tdesorbaix

That is the problem.
The allowedDomains in the config_template.xml is set when you deploy the zimlet.

Just deploy the zimlet once or add the allowedDomains with the CLI.

Can you elaborate on this? CLI?

I've got several of the Zimbra Gallery Zimlets in my Zimbra Desktop _dev folder. They load, but when I right-click on the panelLabel to get a menu, the menu buttons do not work.

Tested on Firefox 3.5 and IE 8 on Windows XP Professional SP3.