Zimbra

crossany · #1 (**permalink**) 03-19-2006, 08:11 PM

I just try to send a soap request like this:
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope">
<soap:Header>
<context xmlns="urn:zimbra">
<authToken>admin@cross.com</authToken>
</context>
</soap:Header>
<soap:Body>
<CreateAccountRequest xmlns="urn:zimbraAdmin">
<name>rush@cross.com</name>
<password>zimbra</password>
</CreateAccountRequest>
</soap:Body>
</soap:Envelope>
but I failure who can tell me the right code thank you !

sam · #2 (**permalink**) 03-19-2006, 09:03 PM

The auth token is incorrect. It needs to be what was returned by the server in a previous AuthRequest.

crossany · #3 (**permalink**) 03-20-2006, 08:02 PM

I don't konw what your mean
could you give me a example thank you

sam · #4 (**permalink**) 03-20-2006, 08:22 PM

yeah, first send

<Envelope xmlns="http://www.w3.org/2003/05/soap-envelope">
<Body>
<AuthRequest xmlns="urn:zimbraAccount">
<account by="name">user1</account>
<password>****</password>
</AuthRequest>
</Body>
</Envelope>

you'll get back

<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope">
<soap:Header>...stuff...
</soap:Header>
<soap:Body>
<AuthResponse xmlns="urn:zimbraAccount">
<authToken>...auth_token...</authToken>
<lifetime>172800000</lifetime>
<sessionId id="55">55</sessionId>
</AuthResponse>
</soap:Body>
</soap:Envelope>

You must save the auth_token and sessionId and pass it back to the server in subsequent requests.

crossany · #5 (**permalink**) 03-21-2006, 02:51 AM

I write a Java code like this :
public class NoCertificationHttpsGetSample {
public static void main(String[] args) {
Protocol myhttps = new Protocol("https",
new MySecureProtocolSocketFactory(),7071);
Protocol.registerProtocol("https", myhttps);
HttpClient httpClient = new HttpClient();
httpClient.getHostConfiguration().setHost("192.168 .1.127",7071,myhttps);
String url="https://192.168.1.127:7071/service/admin/soap";
PostMethod postMethod = new PostMethod(url);
postMethod.getParams().setParameter(HttpMethodPara ms.RETRY_HANDLER,
new DefaultHttpMethodRetryHandler());
try{
InputStream soap= new FileInputStream("soap.xml");
postMethod.setRequestBody(soap);
}catch(Exception err){};
try{
int statusCode = httpClient.executeMethod(postMethod);
if (statusCode != HttpStatus.SC_OK) {
System.err.println("Method failed: "+ postMethod.getStatusLine());
}
byte[] responseBody = postMethod.getResponseBody();
System.out.println(new String(responseBody));
} catch (HttpException e) {
System.out.println("Please check your provided https address!");
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally{
postMethod.releaseConnection();
}

}
}
soap.xml like this :
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope">
<soap:Body>
<AuthRequest xmlns="urn:zimbraAdmin">
<name>admin@sina.com</name>
<password>zimbra</password>
</AuthRequest>
</soap:Body>
</soap:Envelope>

this Error like this :

Method failed: HTTP/1.1 500 Internal Server Error
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope"><soap:Body><soap:Fault><soap:Code><soap: Value>soap:Receiver</soap:Value></soap:Code><soap:Reason><soap:Text>system failure: Request not allowed on port 443</soap:Text></soap:Reason><soap

etail><Error xmlns="urn:zimbra"><Code>service.FAILURE</Code><Trace>com.zimbra.cs.service.ServiceException : system failure: Request not allowed on port 443
at com.zimbra.cs.service.ServiceException.FAILURE(Ser viceException.java:99)
at com.zimbra.cs.servlet.ZimbraServlet.service(Zimbra Servlet.java:136)
at javax.servlet.http.HttpServlet.service(HttpServlet .java:802)
at org.apache.catalina.core.ApplicationFilterChain.in ternalDoFilter(ApplicationFilterChain.java:252)
at org.apache.catalina.core.ApplicationFilterChain.do Filter(ApplicationFilterChain.java:173)
at org.apache.catalina.core.StandardWrapperValve.invo ke(StandardWrapperValve.java:214)
at org.apache.catalina.core.StandardContextValve.invo ke(StandardContextValve.java:178)
at org.apache.catalina.core.StandardHostValve.invoke( StandardHostValve.java:126)
at org.apache.catalina.valves.ErrorReportValve.invoke (ErrorReportValve.java:105)
at org.apache.catalina.core.StandardEngineValve.invok e(StandardEngineValve.java:107)
at org.apache.catalina.valves.AccessLogValve.invoke(A ccessLogValve.java:526)
at org.apache.catalina.connector.CoyoteAdapter.servic e(CoyoteAdapter.java:148)
at org.apache.coyote.http11.Http11Processor.process(H ttp11Processor.java:825)
at org.apache.coyote.http11.Http11Protocol$Http11Conn ectionHandler.processConnection(Http11Protocol.jav a:738)
at org.apache.tomcat.util.net.PoolTcpEndpoint.process Socket(PoolTcpEndpoint.java:526)
at org.apache.tomcat.util.net.LeaderFollowerWorkerThr ead.runIt(LeaderFollowerWorkerThread.java:80)
at org.apache.tomcat.util.threads.ThreadPool$ControlR unnable.run(ThreadPool.java:684)
at java.lang.Thread.run(Thread.java:595)
</Trace></Error></soap

etail></soap:Fault></soap:Body></soap:Envelope>

anybody can tell me why
I crazy !

KevinH · #6 (**permalink**) 03-21-2006, 07:30 AM

Are you sure your using the API correctly? Seems the request is going to 443 and not 7071.

crossany · #7 (**permalink**) 03-21-2006, 06:50 PM

I know the port error but if I getMethod from "https://192.168.1.127:7071"
the will response the HTML code so I think it's will be the soap was wrong

KevinH · #8 (**permalink**) 03-21-2006, 08:04 PM

The SOAP url is:

https://192.168.1.127:7071/service/admin/soap

or

https://192.168.1.127/service/soap for user level calls.

crossany · #9 (**permalink**) 03-21-2006, 09:38 PM

I set the URL ="https://192.168.1.127:7071/service/admin/soap" in the java code before but it's also error

sam · #10 (**permalink**) 03-21-2006, 09:47 PM

are you able to login to the admin console? https://<your-server>:7071/zimbraAdmin ?

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