Cron job to get members of ALL distribution lists

[sanford]

Does anybody have an example/advice of using zmprov to get a daily dump of ALL distribution lists with their members?

We'd like to get a daily dump of this to keep our internal records wiki up to date.

I've gotten as far as using 'zmprov gadl > lists.txt' to get the distribution lists, but am stuck at finding a way to list all of the lists members (in one output file, in an automated manner.)

[veronica]

something like :-

for i in `cat lists.txt`
do
zmprov gdlm $i
done

[sanford]

Wound up with this today. (First shell script I've ever made, probably lots wrong with it, but it seems to work.)

#!/bin/sh
PATH=/opt/zimbra/bin:/opt/zimbra/zimbramon:/opt/zimbra/postfix/sbin:/opt/zimbra/openldap/bin:/opt/zimbra/snmp/bin:/opt/zimbra/sleepycat/bin:/opt/zimbra/openssl/bin:/opt/zimbra/java/bin:/usr/kerberos/bin:/usr/local/bin:/bin:/usr/bin; export PATH
cd /tmp/distrolists
sleep 10
zmprov gadl > lists.txt
sleep 10
sed -e 's/^/gdl /' < lists.txt > lists2.txt
sleep 10
zmprov -f lists2.txt > lists3.txt

[veronica]

Good to hear it works for you.