[SOLVED] How to get some detail from contact

[ohm_g7]

I want to get phone number from contact
when I know email account how I get it.
I want to use command line like this

#zmmailbox -a [admin@domain.com] -p [password] -m [user@yourdomain.com] s -t contact "in:Contact AND from:name"

I don't know way I used in and from command than not found anything.
But If I just used from:name ,it 's work.
Anyway the out put not show phone number.

Please tell me I can get this by command line,If I can't how I do for get phone number.
Thank you for reply.

[ohm_g7]

I got the solution.

If I want to find number of user@domain.yourdomain.com
- Use this command for get contact ID.

#zmmailbox -a admin@domain.yourdomain.com.com -p password -m user@domain.yourdomain.com s -t contact 'in:"Contacts"' | grep sws@domain

Note: you need use '" "' if you have space in search.

you got out put like this

3. 2fa6c7f0-2047-4e9d-807f-c35f0322c67e:423 cont sws@domain.yourdomain คุณศิวัฒน์ ศิวะบวร 01/01/70 07:00


This is contact ID --> 2fa6c7f0-2047-4e9d-807f-c35f0322c67e:423
you need to cut only contact ID and send this to next command

- use this command for get phone number

#zmmailbox -a admin@domain.yourdomain.com.com -p password -m user@domain.yourdomain.com getContacts 2fa6c7f0-2047-4e9d-807f-c35f0322c67e:423

out put is all detail in this contact.
you need grep command for get only line you want

Example :
#zmmailbox -a admin@domain.yourdomain.com.com -p password -m user@domain.yourdomain.com getContacts 2fa6c7f0-2047-4e9d-807f-c35f0322c67e:423 | grep assistantPhone

out put is :
assistantPhone: 08-1803-2410

[uxbod]

Excellent Thank you for posting your solution.