[SOLVED] Monthly messages report?

[halley]

Hi guys
sup?

I recieve daily messages report from my server... i need this statistics moth, its is possible?

Thanks mans...

[Dirk]

Hello halley, welcome to the forum. Could you clarify your question a little as I dont quite understand it. Thanks.

[halley]

Hello halley, welcome to the forum. Could you clarify your question a little as I dont quite understand it. Thanks.

I would like to know the possibility of having the monthly number of how many messages come and go. Currently receive an e-mail messages daily from, I wanted the monthly total.

Thanks

[mmorse]

The arguments to zmdailyreport include:
--user <email_address> Report usage for <email_address> only
--mail Send report via email, default is stdout
--now Shortcut for midnight to the current time
--time <start>,<end> Default is midnight to midnight of the previous day
Start and end times must be in YYYYMMDD[hhmmss] format

So you can either-
A) Run it manually:

cd /opt/zimbra/libexec
./zmdailyreport -m -t start,end

Comma included or it wont find the end time.
./zmdailyreport -m -t 20090301112233,2009031211223

You also don't have to be that specific:
./zmdailyreport -m -t 2009,20090312

B) Modify cron:
su - zimbra
contab -e (opens in vim)

# Daily reports
#
10 1 * * * /opt/zimbra/libexec/zmdailyreport -m

You'll want to put in values for -t such that it's auto (make yourself a $datefirstmonth & $datecurrent)

C) Modify /opt/zimbra/libexec/zmdailyreport default to contain *720 or an extra *30 (or so):

# usage: getTimes( now => $Opt{now}, time => $Opt{time} )
sub getTimes {
my &#37;arg = @_;

my ( $start, $end );
if ( $arg{time} ) {
( $start, $end ) = split( /\s*,\s*/, $arg{time} );
$start = timeToSqlTime($start);
$end = timeToSqlTime($end) if ($end);
}
elsif ( $arg{now} ) {
$start = tsToSqlTime( time(), 1 );
$end = tsToSqlTime( time(), 0 );
}
else { # default to the previous day
$start = tsToSqlTime( ( time() - ( 60 * 60 * 24 ) ), 1 );
$end = tsToSqlTime( time(), 1 );
}
return ( $start, $end );

Keep in mind it checks the logger DB, so the results you get are going to be limited by:

zimbraLogRawLifetime (default 31d) - lifetime (nnnnn[hmsd]) of raw log rows in consolidated logger tables
zimbraLogSummaryLifetime (default 730d)- lifetime (nnnnn[hmsd]) of summarized log rows in consolidated logger tables

Adjust with: zmprov mcf zimbraLogAttribute Xd

[mmorse]

I should clarify the comma is important or it wont find the end time.

A) Run it manually:
cd /opt/zimbra/libexec
./zmdailyreport -m -t 20090301112233,2009031211223

You also don't have to be that specific:
./zmdailyreport -m -t 2009,20090312

[halley]

Work Fine man... very thanks... very...

[mmorse]

Edit: Work Fine man... very thanks... very...

Cool

Thanks Mmorse, i exec this command [zimbra@mail libexec]$ ./zmdailyreport -m -t 20081219000000,20090311000000

and not recieve any result, this send mail for admin@mail.com ? Thanks man

Without -m presents it to your console/stdout.

Specifying -m sends it to the email specified in localconfig:
zmlocalconfig -e smtp_destination=admin@domain.com

Also relevant to that is:
smtp_source=admin@domain.com (the from)
smtp_notify=yes
zimbra_mtareport_max_recipients=50
zimbra_mtareport_max_senders=50